I will be showing both classes at the same time so you do it like this:so you make a line then you do a jump +3 on the jump then underneath you write 3 then you do another jump then you write 6 then you do another and that is 9,Then you do a jump of 7 and that will equal 16 then you do another and that will equal 23,To be continued.
But you have to do a number line so you would do and jump that is +3 in the middle in the jump then you do another jump and another jump,but you have to do another jump that is +7 and another jump and another.Then you do a jump that is +3 and another jump.Then you do a jump that +7 and you don`t do another you do +3 so that will =52 so you do 3+3+3+7+7+3+3+7+7.Now you do 4 times 7 =28 and 8 times 3 =28 so you do 28+24=52 so there you go.
I will be showing both classes at the same time so you do it like this:so you make a line then you do a jump +3 on the jump then underneath you write 3 then you do another jump then you write 6 then you do another and that is 9,Then you do a jump of 7 and that will equal 16 then you do another and that will equal 23,To be continued.
ReplyDeleteThen you do 3+3+3+7+7+3+3+7+3.
ReplyDeleteBut you have to do a number line so you would do and jump that is +3 in the middle in the jump then you do another jump and another jump,but you have to do another jump that is +7 and another jump and another.Then you do a jump that is +3 and another jump.Then you do a jump that +7 and you don`t do another you do +3 so that will =52 so you do 3+3+3+7+7+3+3+7+7.Now you do 4 times 7 =28 and 8 times 3 =28 so you do 28+24=52 so there you go.
DeleteThen you do 4+7=28 times and 8+3 24 then you and it up so 28+24=52 so there you go
ReplyDeleteBut is there another way of solving the problem Abdi?
DeleteYes Mr Highman there is a way you could do 8 times 4=32 and 4 times 5=20 so 32+20=52
DeleteBut the monsters have either 3 or 7 legs, so it must be multiples of 3 or 7.
Delete3x7=21 they might have had 21 legs
ReplyDelete7x3=21 it might be 21 even if i put 3x7
ReplyDelete